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Two radioactive substance X and Y initia...

Two radioactive substance `X` and `Y` initially contain equal number of nuclei. `X` has a half life of `1` hour and `Y` has a half-life of `2` hours. After 2 hours the ratio of activity of `X` to that of `y` is

A

`1:4`

B

`1:2`

C

`1:1`

D

`2:1`

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To solve the problem of finding the ratio of activity of two radioactive substances \(X\) and \(Y\) after 2 hours, we can follow these steps: ### Step 1: Understand the given data - Both substances \(X\) and \(Y\) initially contain equal number of nuclei, denoted as \(N_0\). - The half-life of substance \(X\) is 1 hour. - The half-life of substance \(Y\) is 2 hours. ### Step 2: Define the formula for activity The activity \(A\) of a radioactive substance is given by the formula: \[ A = A_0 \left(\frac{1}{2}\right)^{\frac{t}{t_{1/2}}} \] where: - \(A_0\) is the initial activity, - \(t\) is the time elapsed, - \(t_{1/2}\) is the half-life of the substance. ### Step 3: Calculate the activity of substance \(X\) after 2 hours For substance \(X\): - Initial activity \(A_{0X} = N_0\) (since the initial number of nuclei is the same). - Half-life \(t_{1/2X} = 1\) hour. - Time \(t = 2\) hours. Using the formula: \[ A_X = A_{0X} \left(\frac{1}{2}\right)^{\frac{2}{1}} = N_0 \left(\frac{1}{2}\right)^{2} = N_0 \cdot \frac{1}{4} = \frac{N_0}{4} \] ### Step 4: Calculate the activity of substance \(Y\) after 2 hours For substance \(Y\): - Initial activity \(A_{0Y} = N_0\). - Half-life \(t_{1/2Y} = 2\) hours. - Time \(t = 2\) hours. Using the formula: \[ A_Y = A_{0Y} \left(\frac{1}{2}\right)^{\frac{2}{2}} = N_0 \left(\frac{1}{2}\right)^{1} = N_0 \cdot \frac{1}{2} = \frac{N_0}{2} \] ### Step 5: Find the ratio of activities \(A_X\) to \(A_Y\) Now, we can find the ratio of the activities: \[ \text{Ratio} = \frac{A_X}{A_Y} = \frac{\frac{N_0}{4}}{\frac{N_0}{2}} = \frac{1/4}{1/2} = \frac{1}{4} \cdot \frac{2}{1} = \frac{1}{2} \] ### Step 6: Conclusion The ratio of the activity of \(X\) to that of \(Y\) after 2 hours is: \[ \text{Ratio} = 1 : 2 \] ### Final Answer Thus, the final answer is \(1 : 2\). ---

To solve the problem of finding the ratio of activity of two radioactive substances \(X\) and \(Y\) after 2 hours, we can follow these steps: ### Step 1: Understand the given data - Both substances \(X\) and \(Y\) initially contain equal number of nuclei, denoted as \(N_0\). - The half-life of substance \(X\) is 1 hour. - The half-life of substance \(Y\) is 2 hours. ### Step 2: Define the formula for activity ...
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