Oxidation number of iron in Hematite, Magnetite and Siderite respectively is :

Options

A. `+3, + (5)/(2)` and + 1
B. `+2, + 1` and + 3
C. `+3, + (4)/(3)` and + 3
D. `+ 3, + (8)/(3)` and + 2

Explanation

To determine the oxidation number of iron in Hematite, Magnetite, and Siderite, we will analyze the chemical formulas of each mineral and apply the rules for calculating oxidation states.

### Step-by-Step Solution:

1. **Hematite (Fe2O3)**:
- The formula for Hematite is Fe2O3.
- Let the oxidation state of iron be \( x \).
- The oxidation state equation can be set up as follows:
\[ 2x + 3(-2) = 0 \]
- Simplifying this gives:
\[ 2x - 6 = 0 \]
\[ 2x = 6 \]
\[ x = +3 \]
- Therefore, the oxidation number of iron in Hematite is **+3**.

2. **Magnetite (Fe3O4)**:
- The formula for Magnetite is Fe3O4, which can also be expressed as Fe2O3·FeO.
- Let the oxidation state of iron be \( x \).
- The oxidation state equation can be set up as follows:
\[ 3x + 4(-2) = 0 \]
- Simplifying this gives:
\[ 3x - 8 = 0 \]
\[ 3x = 8 \]
\[ x = \frac{8}{3} \]
- Therefore, the oxidation number of iron in Magnetite is **+\(\frac{8}{3}\)**.

3. **Siderite (FeCO3)**:
- The formula for Siderite is FeCO3.
- Let the oxidation state of iron be \( x \).
- The oxidation state equation can be set up as follows:
\[ x + (1)(-2) + (3)(-2) = 0 \]
- Simplifying this gives:
\[ x - 2 = 0 \]
\[ x = +2 \]
- Therefore, the oxidation number of iron in Siderite is **+2**.

### Final Answer:
The oxidation numbers of iron in Hematite, Magnetite, and Siderite are respectively **+3, +\(\frac{8}{3}\), and +2**.