Al has a smaller first ionization enthalpy than Mg. Consider the following statements`:`
I. It is easier to remove 3p electron than 3s electron .
II . 3p electron of Al is more shielded from the nucleus by the inner coreof electron than the 3s electrons of Mg
III. 3s electron hasmore penetration power than 3p electron
IV. Atomic radius of Al is more than Mg ( atomic number Al=13, Mg = 12 )
The correct statements are `:`

Options

A. I, II and IV
B. I,II and III
C. II, III and IV
D. I, III and IV

Explanation

To solve the question regarding the first ionization enthalpy of Aluminum (Al) and Magnesium (Mg), we will analyze each statement provided in the question.

### Step-by-Step Solution:

1. **Understanding Ionization Energy**:
- Ionization energy is the energy required to remove an electron from an atom in its gaseous state. The first ionization energy of Al is smaller than that of Mg, which means it is easier to remove an electron from Al than from Mg.

2. **Electronic Configurations**:
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