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The area bounded by the curves x + y = ...

The area bounded by the curves `x + y = 2` and `y = x^2 `above x-axis in the first quadrant is:

A

`1/2`

B

`2/3`

C

`(10)/(12)`

D

`6/5`

Text Solution

Verified by Experts

The correct Answer is:
C
Solving `x+y=2 & y=x^(2) implies x=-2,1`
`therefore`Area of OBAM`=int_(0)^(1)x^(2)dx +int_(1)^(2)(2-x)dx`
`=(1)/(3)+(2x-(x^(2))/(2))|_(1)^(2)=(5)/(6)=(10)/(12)`.
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