Variance of 1st 10 natural nos. is m & mean of first 10 odd natural number in n then `m//n` is

Options

A. `(33)/(41)`
B. `(40)/(33)`
C. `(41)/(33)`
D. `(33)/(40)`

Answer

D

Explanation

`m=sigma^(2)=(sumx_(c)^(2))/(n)-(sumoverline(x))^(2)=(10*11*21)/(6xx10)-(10*1*11)/(2*10))^(2)`
`m=(77)/(2)-(121)/(4)=(154-121)/(4)" "m=(33)/(4)`.
`n=mean=(1+3+5+ . .. )/(10)=(10^(2))/(10)=10" "therefore (m)/(n)=(33)/(40)`.