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If tan prop &tan beta are the roots of t...

If tan `prop` &tan `beta` are the roots of the equation `bx^2+ax-1=0,bcancel=0` and `tan(prop+beta)=2` then `a+2b+2` is equal to ....

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The correct Answer is:
A
`because tanalpha+tanbeta=-alpha//b," "tanalpha*tanbeta=-1//b`
`therefore tan(alpha+beta)=2=(-(a)/(b))/(1+(1)/(b))`
`implies 2b+2=-a,a+2b+2=0`.
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