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If the magnetic field in a plane electro...

If the magnetic field in a plane electromagnetic wave is given by ` vec(B) = 6 xx 10^(-8) sin (1.6 xx 10^(3) x + 48 xx 10^(10)t) hatj T` ,. What will be expression for electric filed ?

A

`vec(E) = 2 sin (1.6 xx 10^(3) x 48xx 10^(10) t) hati v//m`

B

`vec(E) = 18 sin (1.6 xx 10^(3) x+ 48xx 10^(10) t) hatk v//m`

C

`vec(E) = 6 sin (1.6 xx 10^(3) x+ 48xx 10^(10) t) hati v//m`

D

`vec(E) = 6xx 10^(-18)sin (1.6 xx 10^(3) x+ 48xx 10^(10) t) hati v//m`

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AI Generated Solution

The correct Answer is:
To find the expression for the electric field \( \vec{E} \) corresponding to the given magnetic field \( \vec{B} \) in a plane electromagnetic wave, we can follow these steps: ### Step 1: Identify the given magnetic field The magnetic field is given by: \[ \vec{B} = 6 \times 10^{-8} \sin(1.6 \times 10^{3} x + 4.48 \times 10^{10} t) \hat{j} \, \text{T} \] ### Step 2: Use the relationship between electric field and magnetic field In an electromagnetic wave, the magnitudes of the electric field \( E \) and magnetic field \( B \) are related by the equation: \[ \frac{E}{B} = c \] where \( c \) is the speed of light in vacuum, approximately \( 3 \times 10^8 \, \text{m/s} \). ### Step 3: Calculate the magnitude of the electric field From the equation above, we can express the electric field \( E \) as: \[ E = c \cdot B \] Substituting the values: \[ E = (3 \times 10^8) \cdot (6 \times 10^{-8}) \] ### Step 4: Simplify the expression Calculating the above expression: \[ E = 3 \times 6 = 18 \, \text{V/m} \] ### Step 5: Determine the direction of the electric field Since the magnetic field \( \vec{B} \) is in the \( \hat{j} \) direction and the wave is propagating in the \( \hat{i} \) direction (along the x-axis), the electric field \( \vec{E} \) will be in the \( \hat{k} \) direction (along the z-axis) due to the right-hand rule. ### Step 6: Write the final expression for the electric field Thus, the electric field can be expressed as: \[ \vec{E} = 18 \sin(1.6 \times 10^{3} x + 4.48 \times 10^{10} t) \hat{k} \, \text{V/m} \] ### Final Answer \[ \vec{E} = 18 \times 10^{-8} \sin(1.6 \times 10^{3} x + 4.48 \times 10^{10} t) \hat{k} \, \text{V/m} \] ---
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