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A loop A(0,0,0)B(5,0,0)C(5,5,0)D(0,5,0)E...

A loop A(0,0,0)B(5,0,0)C(5,5,0)D(0,5,0)E(0,5,10) and F(0,0,10) of straight edges has six corner points and two sides. The magnetic field in this region is `vec(B) = (3hati + 4hatk)` T. The quantity of flux through the loop ABCDEFA (in Wb) is

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The correct Answer is:
250

Flux `= 25 xx 4 + 50 xx 3 = 250`
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VMC MODULES ENGLISH-JEE MAIN REVISION TEST - 30 | JEE -2020-PHYSICS
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