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If y = y(x) is the solution of the diff...

If `y = y(x)` is the solution of the differential equation,`x (dy)/(dx) + 5y = 10x^5, x > 0` satisfying `y(1) = 2` then range of `y(x)` for `x > 0` is:

A

`[1,oo)`

B

`[2 , oo)`

C

`(2, oo)`

D

`[4,00)`

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To solve the differential equation \( x \frac{dy}{dx} + 5y = 10x^5 \) with the initial condition \( y(1) = 2 \), we will follow these steps: ### Step 1: Rewrite the Differential Equation We start with the given equation: \[ x \frac{dy}{dx} + 5y = 10x^5 \] We can rewrite it in standard linear form: \[ \frac{dy}{dx} + \frac{5}{x} y = 10x^4 \] ### Step 2: Identify the Integrating Factor The integrating factor \( \mu(x) \) is given by: \[ \mu(x) = e^{\int \frac{5}{x} dx} = e^{5 \ln x} = x^5 \] ### Step 3: Multiply the Equation by the Integrating Factor Now we multiply the entire equation by the integrating factor \( x^5 \): \[ x^5 \frac{dy}{dx} + 5x^4 y = 10x^9 \] This can be rewritten as: \[ \frac{d}{dx}(x^5 y) = 10x^9 \] ### Step 4: Integrate Both Sides Integrating both sides with respect to \( x \): \[ \int \frac{d}{dx}(x^5 y) \, dx = \int 10x^9 \, dx \] This gives us: \[ x^5 y = x^{10} + C \] where \( C \) is the constant of integration. ### Step 5: Solve for \( y \) Now, we solve for \( y \): \[ y = \frac{x^{10} + C}{x^5} = x^5 + \frac{C}{x^5} \] ### Step 6: Apply the Initial Condition We use the initial condition \( y(1) = 2 \): \[ 2 = 1^5 + \frac{C}{1^5} \implies 2 = 1 + C \implies C = 1 \] ### Step 7: Write the Final Solution Thus, the solution to the differential equation is: \[ y = x^5 + \frac{1}{x^5} \] ### Step 8: Find the Range of \( y(x) \) To find the range of \( y(x) = x^5 + \frac{1}{x^5} \) for \( x > 0 \), we can use the AM-GM inequality: \[ \frac{x^5 + \frac{1}{x^5}}{2} \geq \sqrt{x^5 \cdot \frac{1}{x^5}} = 1 \] Thus, \[ x^5 + \frac{1}{x^5} \geq 2 \] The minimum value occurs when \( x^5 = \frac{1}{x^5} \) or \( x = 1 \), giving \( y(1) = 2 \). As \( x \to 0^+ \), \( y \to \infty \) and as \( x \to \infty \), \( y \to \infty \). ### Conclusion The range of \( y(x) \) for \( x > 0 \) is: \[ [2, \infty) \]

To solve the differential equation \( x \frac{dy}{dx} + 5y = 10x^5 \) with the initial condition \( y(1) = 2 \), we will follow these steps: ### Step 1: Rewrite the Differential Equation We start with the given equation: \[ x \frac{dy}{dx} + 5y = 10x^5 \] We can rewrite it in standard linear form: ...
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