Home
Class 12
MATHS
The system of linear equations x - 2y ...

The system of linear equations
`x - 2y + z = 4`
`2x + 3y - 4z = 1`
`x - 9y + (2a + 3)z = 5a + 1`
has infinitely many solution for:

A

`a!= 2`

B

`a = 1`

C

No value of a

D

a = 2

Text Solution

AI Generated Solution

The correct Answer is:
To determine the value of \( a \) for which the given system of linear equations has infinitely many solutions, we need to analyze the coefficients of the equations. The condition for a system of linear equations to have infinitely many solutions is that the determinant of the coefficient matrix must be zero. The given equations are: 1. \( x - 2y + z = 4 \) 2. \( 2x + 3y - 4z = 1 \) 3. \( x - 9y + (2a + 3)z = 5a + 1 \) ### Step 1: Write the coefficient matrix The coefficient matrix \( A \) for the system of equations is: \[ A = \begin{bmatrix} 1 & -2 & 1 \\ 2 & 3 & -4 \\ 1 & -9 & (2a + 3) \end{bmatrix} \] ### Step 2: Calculate the determinant of the coefficient matrix To find the determinant of matrix \( A \), we can use the formula for the determinant of a 3x3 matrix: \[ \text{det}(A) = a(ei - fh) - b(di - fg) + c(dh - eg) \] Where: - \( a = 1, b = -2, c = 1 \) - \( d = 2, e = 3, f = -4 \) - \( g = 1, h = -9, i = (2a + 3) \) Substituting these values into the determinant formula: \[ \text{det}(A) = 1 \cdot (3(2a + 3) - (-4)(-9)) - (-2)(2(2a + 3) - (-4)(1)) + 1(2(-9) - 3(1)) \] ### Step 3: Simplify the determinant expression Calculating each term: 1. First term: \[ 3(2a + 3) - 36 = 6a + 9 - 36 = 6a - 27 \] 2. Second term: \[ -2(4a + 6 - 4) = -2(4a + 2) = -8a - 4 \] 3. Third term: \[ 2(-9) - 3 = -18 - 3 = -21 \] Putting it all together: \[ \text{det}(A) = (6a - 27) + (8a + 4) - 21 \] \[ = 6a - 27 + 8a + 4 - 21 \] \[ = 14a - 44 \] ### Step 4: Set the determinant to zero For the system to have infinitely many solutions, we set the determinant equal to zero: \[ 14a - 44 = 0 \] ### Step 5: Solve for \( a \) Solving for \( a \): \[ 14a = 44 \] \[ a = \frac{44}{14} = \frac{22}{7} \] ### Conclusion The value of \( a \) for which the system of equations has infinitely many solutions is: \[ \boxed{\frac{22}{7}} \]

To determine the value of \( a \) for which the given system of linear equations has infinitely many solutions, we need to analyze the coefficients of the equations. The condition for a system of linear equations to have infinitely many solutions is that the determinant of the coefficient matrix must be zero. The given equations are: 1. \( x - 2y + z = 4 \) 2. \( 2x + 3y - 4z = 1 \) 3. \( x - 9y + (2a + 3)z = 5a + 1 \) ...
Promotional Banner

Topper's Solved these Questions

  • JEE MAIN REVISION TEST - 18

    VMC MODULES ENGLISH|Exercise MATHEMATICS - SECTION 2|5 Videos
  • JEE MAIN REVISION TEST - 13

    VMC MODULES ENGLISH|Exercise MATHEMATICS (SECTION 2)|5 Videos
  • JEE MAIN REVISION TEST - 19

    VMC MODULES ENGLISH|Exercise MATHEMATICS|25 Videos

Similar Questions

Explore conceptually related problems

The system of linear equations x + y + z = 2 2x + 3y + 2z = 5 2x + 3y + (a^(2) - 1)z = a + 1

If the system of linear equations x+ y +z = 5 x+2y +2z = 6 x + 3y + lambdaz = mu, (lambda, mu in R) has infinitely many solutions, then the value of lambda + mu is

If the system of equation x - 2y + 5z = 3 2x - y + z = 1 and 11x - 7y + pz = q has infinitely many solution, then

The system of linear equations x + y + z = 2 2x + y -z = 3 3x + 2y + kz = 4 has a unique solution, if

Let lambda be a real number for which the system of linear equations x + y +z =6, 4x + lambday -lambdaz = lambda -2 and 3x + 2y-4z =-5 has infinitely many solutions. Then lambda is a root of the quadratic equation

If the system fo equations x+y+z = 5 x + 2y + 3z = 9 x + 3y + alphaz = beta has infinitely many solution, then beta - alpha equals

If the system of equations x + 2y + 3z = 4, x+ py+ 2z = 3, x+ 4y +u z = 3 has an infinite number of solutions and solution triplet is

The system of linear equations x + y + z = 0 (2x)/(a) + (3y)/(b) + (4z)/(c ) = 0 (x)/(a) + (y)/(b) + (z)/(c ) = 0 has non trivia solution then

Solve system of linear equations, using matrix method, 2x + 3y +3z = 5 x-2 y + z =-4 , 3x-y - 2z= 3

The system of equations x+2y-4z=3,2x-3y+2z=5 and x -12y +16z =1 has