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P=n(n^(2)-1)(n^(2)-4)(n^(2)-9)…(n^(2)-10...

`P=n(n^(2)-1)(n^(2)-4)(n^(2)-9)…(n^(2)-100)` is always divisible by , `(n in I)` (a) `2!3!4!5!6!` (b) `(5!)^(4)` (c) `(10!)^(2)` (d) `10!11!`

A

`(2r+2)!`

B

`(2r-1)!`

C

`(2r+1)!`

D

none of these

Text Solution

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The correct Answer is:
B, C
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