If cos theta=(a)/(b+c),cos phi=(b)/(a+c)...

If `cos theta=(a)/(b+c),cos phi=(b)/(a+c),cospsi=(c)/(a+b)`, where `theat,phi,psi in (0,pi)` and a,b , c are sides of triangle ABC then find the value of `tan^(2)""(theta)/(2)+tan^(2)""(phi)/(2)+tan^(2)""(psi)/(2)`,

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