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let`ABC` be a right angled triangle at `C. `If the inscribed circle touches the side `AB `at `D` and `(AD) (BD)=11,` then find the area of triangle `ABC.`.

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To find the area of triangle \( ABC \) given that it is a right-angled triangle at \( C \) and that the inscribed circle touches side \( AB \) at point \( D \) with the condition \( AD \cdot BD = 11 \), we can follow these steps: ### Step-by-Step Solution: 1. **Label the Triangle**: Let \( AD = z \), \( BD = y \), and \( CD = x \). Since \( D \) is the point where the incircle touches \( AB \), we have: \[ AB = AD + BD = z + y \] 2. **Using the Tangent Properties**: The lengths of the tangents drawn from a point outside the circle to the circle are equal. Therefore: - \( AE = AD = z \) - \( BF = BD = y \) - \( CE = CF = x \) 3. **Applying the Pythagorean Theorem**: Since triangle \( ABC \) is right-angled at \( C \), we can apply the Pythagorean theorem: \[ AC^2 + BC^2 = AB^2 \] Here, \( AC = AE + CE = z + x \) and \( BC = BF + CF = y + x \). Thus: \[ (z + x)^2 + (y + x)^2 = (z + y)^2 \] 4. **Expanding the Equation**: Expanding both sides: \[ (z^2 + 2zx + x^2) + (y^2 + 2xy + x^2) = (z^2 + 2zy + y^2) \] This simplifies to: \[ z^2 + y^2 + 2zx + 2xy + 2x^2 = z^2 + y^2 + 2zy \] Cancel \( z^2 \) and \( y^2 \) from both sides: \[ 2zx + 2xy + 2x^2 = 2zy \] Dividing by 2: \[ zx + xy + x^2 = zy \] 5. **Substituting the Given Condition**: We know that \( AD \cdot BD = z \cdot y = 11 \). Therefore, we can substitute \( zy = 11 \) into our equation: \[ zx + xy + x^2 = 11 \] 6. **Finding the Area of Triangle \( ABC \)**: The area \( A \) of triangle \( ABC \) can be expressed as: \[ A = \frac{1}{2} \times BC \times AC = \frac{1}{2} \times (y + x) \times (z + x) \] Expanding this: \[ A = \frac{1}{2} \times (xy + xz + yx + x^2) = \frac{1}{2} \times (xy + zx + x^2) \] From our earlier relation, we know \( zx + xy + x^2 = 11 \): \[ A = \frac{1}{2} \times 11 = \frac{11}{2} \] 7. **Final Area Calculation**: Thus, the area of triangle \( ABC \) is: \[ A = 11 \text{ square units} \]
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