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Consider the following two statements : ...

Consider the following two statements :
Statement p : The value of can be derived by taking `theta = 240^(@)` in the equation `2 sin.(theta)/(2) = sqrt(1+ sin theta) - sqrt(1- sin theta)`
Statement q : The angles A, B, C and D of any quadrilateral ABCD satisfy the equation `cos((1)/(2)(A+C)) + cos((1)/(2)(B+D)) = 0`
Then the truth value of p and q are respectively :

A

T, T

B

F, F

C

F, T

D

T, F

Text Solution

AI Generated Solution

The correct Answer is:
To analyze the truth values of the statements p and q, we will go through each statement step by step. ### Step 1: Evaluate Statement p **Statement p**: The value of can be derived by taking `theta = 240°` in the equation \[ \frac{2 \sin(\theta)}{2} = \sqrt{1 + \sin(\theta)} - \sqrt{1 - \sin(\theta)} \] 1. Substitute \(\theta = 240°\) into the equation: \[ 2 \sin(240°) = \sqrt{1 + \sin(240°)} - \sqrt{1 - \sin(240°)} \] 2. Calculate \(\sin(240°)\): \[ \sin(240°) = -\frac{\sqrt{3}}{2} \] Thus, we have: \[ 2 \left(-\frac{\sqrt{3}}{2}\right) = \sqrt{1 - \frac{\sqrt{3}}{2}} - \sqrt{1 + \frac{\sqrt{3}}{2}} \] Simplifying gives: \[ -\sqrt{3} = \sqrt{1 - \frac{\sqrt{3}}{2}} - \sqrt{1 + \frac{\sqrt{3}}{2}} \] 3. Calculate the right-hand side: - Calculate \(1 - \frac{\sqrt{3}}{2}\): \[ 1 - \frac{\sqrt{3}}{2} = \frac{2 - \sqrt{3}}{2} \] - Calculate \(1 + \frac{\sqrt{3}}{2}\): \[ 1 + \frac{\sqrt{3}}{2} = \frac{2 + \sqrt{3}}{2} \] 4. Substitute these values back into the equation: \[ -\sqrt{3} = \sqrt{\frac{2 - \sqrt{3}}{2}} - \sqrt{\frac{2 + \sqrt{3}}{2}} \] 5. This equation does not hold true, hence **Statement p is false**. ### Step 2: Evaluate Statement q **Statement q**: The angles A, B, C, and D of any quadrilateral ABCD satisfy the equation \[ \cos\left(\frac{1}{2}(A + C)\right) + \cos\left(\frac{1}{2}(B + D)\right) = 0 \] 1. From the properties of a quadrilateral, we know that: \[ A + B + C + D = 360° \] Thus, we can express \(A + C\) and \(B + D\) as: \[ A + C = 360° - (B + D) \] 2. Therefore, we can write: \[ \frac{1}{2}(A + C) + \frac{1}{2}(B + D) = 180° \] 3. This implies: \[ \cos\left(\frac{1}{2}(A + C)\right) = -\cos\left(\frac{1}{2}(B + D)\right) \] 4. Hence, it follows that: \[ \cos\left(\frac{1}{2}(A + C)\right) + \cos\left(\frac{1}{2}(B + D)\right) = 0 \] 5. Therefore, **Statement q is true**. ### Conclusion - **Statement p** is **false**. - **Statement q** is **true**. Thus, the truth values of p and q are respectively: **false** and **true**.
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