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ABCD is a trapezium such that AB and CD ...

ABCD is a trapezium such that AB and CD are parallel and `BC bot CD`. If `angleADB = theta, BC = p and CD = q`, then AB is equal to

A

`(p^(2) + q^(2) cos theta)/(p cos theta + q sin theta)`

B

`(p^(2) + q^(2))/(p^(2) cos theta + q^(2) sin theta)`

C

`((p^(2)+q^(2))sin theta)/((p cos theta + q sin theta)^(2))`

D

`((p^(2)+q^(2))sin theta)/((p cos theta + q sin theta)`

Text Solution

Verified by Experts

The correct Answer is:
D
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