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Internal bisector of angle A of Delta A...

Internal bisector of `angle A ` of `Delta ABC` meets side BC to D. A line drawn through D perpendicular to AD intersects the side AC at E and side AB at. F. If a,b,c represent sides of `Delta ABC,` then

A

AE is HM of b and c

B

`AD = (2bc)/(b+c)cos.(A)/(2)`

C

`EF = (4bc)/(b+c) sin.(A)/(2)`

D

`Delta AEF` is isosceles

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The correct Answer is:
A, B, C, D
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VMC MODULES ENGLISH-PROPERTIES OF TRIANGLE-JEE Advanced (Archive)
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