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If a circle of radius R passes through the origin O and intersects the coordinate axes at A and B, then the locus of the foot of perpendicular from O on AB is

A

`9 ( x^(2) + y^(2))=4a^(2)`

B

`9(x^(2) + y^(2)) = a^(2)`

C

`9(x^(2) +y^(2)) =2a^(2)`

D

`9(x^(2) + y^(2)) =8a^(2)`

Text Solution

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a
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