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Two tangents to the circle x^2 +y^2=4 at...

Two tangents to the circle `x^2 +y^2=4` at the points `A` and `B` meet at `P(-4,0)`, The area of the quadrilateral `PAOB`, where `O` is the origin, is

A

4

B

`6 sqrt(2)`

C

`4 sqrt(3)`

D

None of these

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The correct Answer is:
To find the area of the quadrilateral \( PAOB \), where \( P \) is the point where the tangents meet, \( A \) and \( B \) are the points of tangency on the circle, and \( O \) is the origin, we can follow these steps: ### Step 1: Understand the Circle The equation of the circle is given by: \[ x^2 + y^2 = 4 \] This means the center of the circle \( O \) is at \( (0, 0) \) and the radius \( r \) is \( 2 \) (since \( r^2 = 4 \)). **Hint:** Identify the center and radius of the circle from its equation. ### Step 2: Find the Coordinates of Points A and B Since \( P(-4, 0) \) is outside the circle, we can find the points of tangency \( A \) and \( B \) using the property of tangents. The distance from the center \( O \) to point \( P \) is \( OP = 4 \). The length of the tangent from \( P \) to the circle can be calculated using the Pythagorean theorem: \[ PA^2 = OP^2 - OA^2 \] Where \( OA = 2 \) (the radius). Thus: \[ PA^2 = 4^2 - 2^2 = 16 - 4 = 12 \implies PA = \sqrt{12} = 2\sqrt{3} \] **Hint:** Use the Pythagorean theorem to find the length of the tangents. ### Step 3: Calculate the Angle of Tangents The angle \( \theta \) between the radius and the tangent can be calculated using: \[ \sin \theta = \frac{OA}{OP} = \frac{2}{4} = \frac{1}{2} \] This means \( \theta = 30^\circ \). **Hint:** Relate the lengths of the radius and the tangent to find the angle. ### Step 4: Calculate the Area of Triangle \( POA \) The area of triangle \( POA \) can be calculated using the formula: \[ \text{Area} = \frac{1}{2} \times \text{base} \times \text{height} \] Here, \( PO \) is the base and \( OA \) is the height. The area can also be calculated using: \[ \text{Area} = \frac{1}{2} \times PA \times PO \times \sin \theta \] Substituting the values: \[ \text{Area} = \frac{1}{2} \times 2\sqrt{3} \times 4 \times \sin(30^\circ) = \frac{1}{2} \times 2\sqrt{3} \times 4 \times \frac{1}{2} = 2\sqrt{3} \] **Hint:** Use the area formula for triangles and remember to incorporate the sine of the angle. ### Step 5: Calculate the Area of Quadrilateral \( PAOB \) Since \( PAOB \) consists of two triangles \( POA \) and \( POB \), and both triangles are congruent: \[ \text{Area of } PAOB = 2 \times \text{Area of } POA = 2 \times 2\sqrt{3} = 4\sqrt{3} \] **Hint:** Recognize that the quadrilateral can be divided into two congruent triangles. ### Final Answer Thus, the area of the quadrilateral \( PAOB \) is: \[ \boxed{4\sqrt{3}} \]
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