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If a >2b >0, then find the positive valu...

If `a >2b >0,` then find the positive value of `m` for which `y=m x-bsqrt(1+m^2)` is a common tangent to `x^2+y^2=b^2` and `(x-a)^2+y^2=b^2dot`

A

`( 2b ) /( sqrt( a^(2) - 4b^(2)))`

B

`( sqrt( a^(2) - 4b^(2)))/(2b)`

C

`(2b)/( a-2b)`

D

`(b)/(a-2b)`

Text Solution

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The correct Answer is:
A
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