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If the circles x^2+y^2+2a x+c=0a n dx^2+...

If the circles `x^2+y^2+2a x+c=0a n dx^2+y^2+2b y+c=0` touch each other, then `(a) 1/(a^2)+1/(b^2)=1/c` (b) `1/(a^2)+1/(b^2)=1/(c^2)` (c) `a+b=2c` (d) `1/a+1/b=2/c`

A

`a^(-2) + b^(-2) = c^(-1)`

B

`a^(-2) + b^(-2)= c^(-2)`

C

`a+b= 2c `

D

` (1)/(a) +( 1)/(b) =(2)/( c ) `

Text Solution

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The correct Answer is:
A
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