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Lines 5x + 12y - 10 = 0 and 5x - 12y - 4...

Lines `5x + 12y - 10 = 0` and `5x - 12y - 40 = 0` touch a circle C1 of diameter 6. If the center of C1, lies in the first quadrant then the equation of the circle C2, which is concentric with C1, and cuts intercept of length 8 on these lines

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The correct Answer is:
`( x- 5)^(2) + ( y - 2)^(2) = 5^(2)` \
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VMC MODULES ENGLISH-CIRCLES-JEE ADVANCED ( ARCHIVE )
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  13. Find the intervals of the values of a for which the line y+x=0 bisects...

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  18. Two parallel chords of a circle of radius 2 are at a distance. sqrt(3+...

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  19. A line y=mx+1 meets the circle (x-3)^(2)+(y+2)^(2)=25 at point P and Q...

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