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Differentiate each of the following with respect to x in following question: `(x^(5)-cosx)/(sinx)`

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To differentiate the function \( y = \frac{x^5 - \cos x}{\sin x} \) with respect to \( x \), we will use the quotient rule of differentiation. The quotient rule states that if you have a function in the form \( \frac{u}{v} \), then the derivative is given by: \[ \frac{dy}{dx} = \frac{v \frac{du}{dx} - u \frac{dv}{dx}}{v^2} \] where \( u = x^5 - \cos x \) and \( v = \sin x \). ### Step 1: Identify \( u \) and \( v \) Let: - \( u = x^5 - \cos x \) - \( v = \sin x \) ### Step 2: Differentiate \( u \) and \( v \) Now we need to find \( \frac{du}{dx} \) and \( \frac{dv}{dx} \). 1. Differentiate \( u \): \[ \frac{du}{dx} = \frac{d}{dx}(x^5) - \frac{d}{dx}(\cos x) = 5x^4 + \sin x \] 2. Differentiate \( v \): \[ \frac{dv}{dx} = \frac{d}{dx}(\sin x) = \cos x \] ### Step 3: Apply the Quotient Rule Now we apply the quotient rule: \[ \frac{dy}{dx} = \frac{\sin x (5x^4 + \sin x) - (x^5 - \cos x)(\cos x)}{\sin^2 x} \] ### Step 4: Simplify the Expression Now we simplify the numerator: 1. Expand the numerator: \[ \sin x (5x^4 + \sin x) = 5x^4 \sin x + \sin^2 x \] \[ (x^5 - \cos x)(\cos x) = x^5 \cos x - \cos^2 x \] 2. Combine the terms: \[ \text{Numerator} = 5x^4 \sin x + \sin^2 x - (x^5 \cos x - \cos^2 x) \] \[ = 5x^4 \sin x + \sin^2 x - x^5 \cos x + \cos^2 x \] Thus, the derivative can be expressed as: \[ \frac{dy}{dx} = \frac{5x^4 \sin x + \sin^2 x - x^5 \cos x + \cos^2 x}{\sin^2 x} \] ### Final Result The final result for the derivative of the function \( y = \frac{x^5 - \cos x}{\sin x} \) is: \[ \frac{dy}{dx} = \frac{5x^4 \sin x - x^5 \cos x + \sin^2 x + \cos^2 x}{\sin^2 x} \]
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VMC MODULES ENGLISH-DIFFERENTIAL CALCULUS-JEE Advanced (Archive)
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