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If f(x)={(x/(1+e^(1//x)),x!=0),(0,x=0):}...

If `f(x)={(x/(1+e^(1//x)),x!=0),(0,x=0):}` then at `x=0`

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The correct Answer is:
`f'(0^(+))=0,f'(0^(-))=1`
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VMC MODULES ENGLISH-DIFFERENTIAL CALCULUS-JEE Advanced (Archive)
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