The value of the expression `|vecaxxvecb|^(2)+(veca.vecb)^(2)` is….. .

Evaluate the expression (veca-vecb)xx(veca+vecb)=

If vecp=(vecbxxvecc)/([(veca,vecb,vecc)]),vecq=(veccxxveca)/([(veca,vecb,vecc)]),vecr=(vecaxxvecb)/([(veca,vecb,vecb)]) where veca,vecb,vecc are three non-coplanar vectors, then the value of the expression (veca+vecb+vecc).(vecp+vecq+vecr) is

If vecP = (vecbxxvecc)/([vecavecbvecc]).vecq=(veccxxveca)/([veca vecb vecc])and vecr = (vecaxxvecb)/([veca vecbvecc]), " where " veca,vecb and vecc are three non- coplanar vectors then the value of the expression (veca + vecb + vecc ). (vecq+ vecq+vecr) is

If vecp = (vecbxxvecc)/([vecavecbvecc]), vecq=(veccxxveca)/([veca vecb vecc])and vecr = (vecaxxvecb)/([veca vecbvecc]), " where " veca,vecb and vecc are three non- coplanar vectors then the value of the expression (veca + vecb + vecc ). (vecp+ vecq+vecr) is (a)3 (b)2 (c)1 (d)0

Let veca,vecb,vecc be three noncolanar vectors and vecp,vecq,vecr are vectors defined by the relations vecp= (vecbxxvecc)/([veca vecb vecc]), vecq= (veccxxveca)/([veca vecb vecc]), vecr= (vecaxxvecb)/([veca vecb vecc]) then the value of the expression (veca+vecb).vecp+(vecb+vecc).vecq+(vecc+veca).vecr . is equal to (A) 0 (B) 1 (C) 2 (D) 3

If veca and vecb are any two vectors , then prove that |vecaxxvecb|^(2)=|veca|^(2)|vecb|^(2)-(veca.vecb)^(2)=|{:(veca.veca,veca.vecb),(veca.vecb,vecb.vecb):}| or |vecaxxvecb|^(2)+(veca.vecb)^(2)=|veca|^(2)|vecb|^(2) (This is also known as Lagrange identily)

IF veca and vecb re two vectors show that |vecaxxvecb|^2=a^2b^2-(veca.vecb)^2

If veca and vecb be any two mutually perpendiculr vectors and vecalpha be any vector then |vecaxxvecb|^2 ((veca.vecalpha)veca)/(|veca|^2)+|vecaxxvecb|^2 ((vecb.vecalpha)vecb)/(|vecb|^2)-|vecaxxvecb|^2vecalpha= (A) |(veca.vecb)vecalpha|(vecaxxvecb) (B) [veca vecb vecalpha](vecbxxveca) (C) [veca vecb vecalpha](vecaxxvecb) (D) none of these

If veca and vecb are two vectors , then prove that (vecaxxvecb)^(2)=|{:(veca.veca" ",veca.vecb),(vecb.veca" ",vecb.vecb):}|

If veca and vecb are two vectors , then prove that (vecaxxvecb)^(2)=|{:(veca.veca" ",veca.vecb),(vecb.veca" ",vecb.vecb):}|