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If in triangle ABC, vec(AB) = vecu/|vec...

If in triangle ABC, ` vec(AB) = vecu/|vecu|-vecv/|vecv| and vec(AC) = (2vecu)/|vecu| , " where " |vecu| ne |vecv|` , then `(a)1 + cos 2A + cos 2B + cos 2C=0` (b)`sin A = cos C` (c)projection of AC on BC is equal to BC (d) projection of AB on BC is equal to AB

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