A particle acted upon by constant forces...

A particle acted upon by constant forces `4hati+hatj-3hatk and 3hati + hatj-hatk` is displaced from the point `hati+2hatj+3hatk` to point `5hati+4hatj+hatk`. The total work done by the forces in SI unit is

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A particle acted upon by constant forces 4hati +hatj- 4 hatk and 3hati + hatj - hatk is displacment from the point hati+ 2hatj+ hatk to point 5hati + 4hatj +hatk .Total work done by the forces in SI unit is :

A paticle acted on by constant forces 4hati+hatj-3hatk and 3hati+hatj-hatk is displaced from the point hati+2hatj+3hatk to 5hati+4hatj+hatk . Find the work done

Work done by a force F=(hati+2hatj+3hatk) acting on a particle in displacing it from the point r_(1)=hati+hatj+hatk to the point r_(2)=hati-hatj+hat2k is

A constant force vecF=(3hati+2hatj+2hatk) N acts on a particle displacing it from a position vec(r_1)=(-hati+hatj-2hatk)m to a new position vecr_2=(hati-hatj+3hatk)m . Find the work done by the force.

Unit vector perpnicular to vector A=-3hati-2hatj -3hatk and 2hati + 4hatj +6hatk is

A uniform force of (3hati+hatj) N acts on a particle of mass 2kg. Hence, the particle is displaced from position (2hati+hatk) m to position (4hati+3hatj-hatk) m. The work done by the force on the particle is

Work done when a force F=(hati + 2hat(j) + 3hatk) N acting on a particle takes it from the point r_(1) =(hati + hatk) the point r_(2) =(hati -hatj + 2hatk) is .

If vecF = 3hati + 4hatj+5hatk and vecS=6hati +2hatj+5hatk , the find the work done.

VMC MODULES ENGLISH-VECTORS -JEE MAIN (ARCHIVE)

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