Home
Class 12
CHEMISTRY
Aluminium chloride exists as a dimer, Al...

Aluminium chloride exists as a dimer, `Al_(2)Cl_(6)` in solid state as well as in solution of non-polar solvents such as benzene. When dissolved in water, it gives :

A

`Al^(3+)+3Cl^(-)`

B

`[Al(H_(2)O)_(6)]^(3+)+3Cl^(-)`

C

`[Al(OH)_(6)]^(3-)+3HCl`

D

`Al_(2)O_(3)+6HCl`

Text Solution

Verified by Experts

Promotional Banner

Topper's Solved these Questions

  • p-BLOCK ELEMENTS-1

    VMC MODULES ENGLISH|Exercise LEVEL 2|73 Videos

  • p-BLOCK ELEMENTS-1

    VMC MODULES ENGLISH|Exercise JEE Main Archive|34 Videos

  • p-BLOCK ELEMENTS-1

    VMC MODULES ENGLISH|Exercise JEE Advanced Archive|48 Videos

  • MOCK TEST 9

    VMC MODULES ENGLISH|Exercise CHEMISTRY (SECTION 2)|5 Videos

  • PERIODIC PROPERTIES OF ELEMENTS

    VMC MODULES ENGLISH|Exercise IMPECCABLE|50 Videos

Similar Questions

Explore conceptually related problems

Anhydrous aluminium chloride (Al_(2)Cl_(6)) is covalent compound and soluble in water giving:

Why boron halides do not exists as a dimer. While AlCl_(3) exists as Al_(2)Cl_(6) ?

The small size and high charge of Al^(3+) ion gives it a high charge density which is responsible for its tendency to show (a) covalency in its compounds in the gaseous state (b) high hydration energy which stabilizes its compounds in solution, and (c) high lattice energy of its compounds in the solid state. Thus aluminium can forms both covalent and ionic bond. Like halides of boron, halides of aluminium do not show back bonding because of increase in size of aluminium. Actually aluminium atoms complete their octets by forming dimers. Thus chloride and bromide of aluminium exist as dimers, both in the vapour state and in polar-solvents like benzene while the corresponding boron halides exists as monomer. In boron trihalides the extent of back bonding decreases with increases with increase in size of halogens and thus lewis acid character increases. All BX_(3) are hydrolysed by water but BF_(3) shows a different behaviour. Which of the following statements about anhydrous aluminium chloride is correct ?

The small size and high charge of Al^(3+) ion gives it a high charge density which is responsible for its tendency to show (a) covalency in its compounds in the gaseous state (b) high hydration energy which stabilizes its compounds in solution, and (c) high lattice energy of its compounds in the solid state. Thus aluminium can forms both covalent and ionic bond. Like halides of boron, halides of aluminium do not show back bonding because of increase in size of aluminium. Actually aluminium atoms complete their octets by forming dimers. Thus chloride and bromide of aluminium exist as dimers, both in the vapour state and in polar-solvents like benzene while the corresponding boron halides exists as monomer. In boron trihalides the extent of back bonding decreases with increases with increase in size of halogens and thus lewis acid character increases. All BX_(3) are hydrolysed by water but BF_(3) shows a different behaviour. Which of the following reaction is incorrect ?

Assertion (A): Iodine is more soluble in C Cl_(4) than in water. Reason(R ): Non-polar solutes are more soluble in non-polar solvents.

The change in hybridization of aluminium when Al_(2)Cl_(6) decomposes in the gas phase is :

A compound of iron exists as a dimer in vapour state. It is hygroscopic in nature and disolves in water giving brown acidic solution. The compound is

Explain the following: (a) Sodium chloride is an ionic compound which does not conduct electricity in solid state whereas it does conduct electricity in molten state as well as in aqueous solution. (b) Reactivity of aluminium decrease if it is dipped in nitric acid. (c) Metals like calcium and magnesium are never found in their free state in nature.

A white solid P, on strong heating, decomposes to give reddish brown gas R and a residue Q. The residue R is yellow when hot and white when cold. The solution of white solid P in water gives white precipitate S, with concentrated sodium hydroxide. The white precipitate S dissolves in excess of sodium hydroxide solution to form colourless solution. Another sample of the solid P in water is mixed with ferrous sulphate solution and then to this solution are added a few drops of conc. sulphuric acid. A brown ring is formed at the junction of liquids. Answer the following questions: Name the salt formed when S dissolves in excess of sodium hydroxide.

When 16.8g of white solid X was heated, 4.4 g of acid gas A that turned lime water milky was driven off together with 1.8 g of a gas B which condensed to a colourless liquid. The solid that remained Y dissolved in water to give an alkaline solution , which with excess barium chloride solution gave a white precipitate Z .THe precipitate effervence with acid giving carbon dioxide. identify A,B and Y and write the equation for the decomposition of X

VMC MODULES ENGLISH-p-BLOCK ELEMENTS-1-LEVEL 1
  1. The structure of diborane (B(2)H(6)) contains :

    Text Solution

    |

  2. BCl(3)+H(2)O rarr X The products fored in the above reaction are

    Text Solution

    |

  3. Aluminium chloride exists as a dimer, Al(2)Cl(6) in solid state as wel...

    Text Solution

    |

  4. Al(4)C(3) is a ionic carbide, named as:

    Text Solution

    |

  5. बोरिक ऐसिड अम्ल है, क्योंकि

    Text Solution

    |

  6. Heating an aqueous solution of aluminium chloride to dryness will give

    Text Solution

    |

  7. The correct order of Lewis acidic strength of boron trihalides :

    Text Solution

    |

  8. In diborane, the two H-B-H angles are nearly

    Text Solution

    |

  9. In group 13, Tl (thalium) shows +1 oxidation state while other members...

    Text Solution

    |

  10. Correct order of bond angles in the given compounds is/are

    Text Solution

    |

  11. The correct order of increasing atomic radii, is :

    Text Solution

    |

  12. Which type of silicate is shown in the given figure ?

    Text Solution

    |

  13. Buckminister-fullerene is a variety of :

    Text Solution

    |

  14. The basic structural unit in silicates is

    Text Solution

    |

  15. On strong heating lead nitrate gives:

    Text Solution

    |

  16. Among the following substituted silanes, the one which will give rise ...

    Text Solution

    |

  17. Identify B in the following H(4)SiO(4) underset(-H(2)O) overset(1000^(...

    Text Solution

    |

  18. In silica (SiO(2)) each silicon is bonded to :

    Text Solution

    |

  19. The incorrect statements among the following is/are : I. Fullerene ...

    Text Solution

    |

  20. The stability of dihalides of Si, Ge, Sn and Pb increases steadily in ...

    Text Solution

    |