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Prove that |overset(rarr)a-overset(rarr)...

Prove that `|overset(rarr)a-overset(rarr)b|ge|overset(rarr)a|-|overset(rarr)b|` When does the equally holds?

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To prove the inequality \(|\vec{a} - \vec{b}| \geq |\vec{a}| - |\vec{b}|\), we will follow these steps: ### Step 1: Start with the given inequality We need to prove that: \[ |\vec{a} - \vec{b}| \geq |\vec{a}| - |\vec{b}| \] ...
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Let overset(rarr)C = overset(rarr)A+overset(rarr)B then :

If |overset(rarr)A-overset(rarr)B|=|overset(rarr)A|-|overset(rarr)B| the angle between overset(rarr)A and overset(rarr)B is

Dot product of two vectors overset(rarr)A and overset(rarr)B is defined as overset(rarr)A.overset(rarr)B=AB cos phi , where phi is angle between them when they are drawn with tails coinciding. For any two vectors . This means ovsert(rarr)A . overset(rarr)B=overset(rarr)B. overset(rarr)A that . The scalar product obeys the commutative law of multiplication, the order of the two vectors does not matter. The vector product of two vectors overset(rarr)A and overset(rarr)B also called the cross product, is denoted by overset(rarr)A xx overset(rarr)B . As the name suggests, the vector product is itself a vector. overset(rarr)C=overset(rarr)A xx overset(rarr)B then C=AB sin theta , For non zero vectors overset(rarr)A, overset(rarr)B, overset(rarr)C,|(overset(rarr)Axxoverset(rarr)B).overset(rarr)C|=|overset(rarr)A||overset(rarr)B||overset(rarr)C| holds if and only if

If |overset(rarr)A+overset(rarr)B|=|overset(rarr)A-overset(rarr)B| what is the angle between overset(rarr)A and overset(rarr)B ?

At what angle the two force overset(rarr)A+overset(rarr)B and overset(rarr)A-overset(rarr)B act so that their resultant is sqrt(3A^(2)+B^(2)) ?

Projection of overset(rarr)P on overset(rarr)Q is :

Dot product of two vectors overset(rarr)A and overset(rarr)B is defined as overset(rarr)A.overset(rarr)B=aB cos phi , where phi is angle between them when they are drawn with tails coinciding. For any two vectors . This means overset(rarr)A . overset(rarr)B=overset(rarr)B. overset(rarr)A that . The scalar product obeys the commutative law of multiplication, the order of the two vectors does not matter. The vector product of two vectors overset(rarr)A and overset(rarr)B also called the cross product, is denoted by overset(rarr)A xx overset(rarr)B . As the name suggests, the vector product is itself a vector. overset(rarr)C=overset(rarr)A xx overset(rarr)B then C=AB sin theta , overset(rarr)A=hat i+ hat j-hatk and overset(rarr)B=2 hat i +3 hat j +5 hat k angle between overset(rarr)A and overset(rarr)B is

Dot product of two vectors overset(rarr)A and overset(rarr)B is defined as overset(rarr)A.overset(rarr)B=aB cos phi , where phi is angle between them when they are drawn with tails coinciding. For any two vectors . This means overset(rarr)A . overset(rarr)B=overset(rarr)B. overset(rarr)A that . The scalar product obeys the commutative law of multiplication, the order of the two vectors does not matter. The vector product of two vectors overset(rarr)A and overset(rarr)B also called the cross product, is denoted by overset(rarr)A xx overset(rarr)B . As the name suggests, the vector product is itself a vector. overset(rarr)C=overset(rarr)A xx overset(rarr)B then C=AB sin theta , A force overset(rarr)F=3hat i +c hat j + 2 hatk acting on a particle causes a displacement d=4hat i- 2 hat j + 3 hat k . If the work done (dot product of force and displacement) is 6J then the value of c is :

If overset(rarr)B=noverset(rarr)A and overset(rarr)A is antiparallel with overset(rarr)B , then n is :

what is the angle between (overset(rarr)P+overset(rarr)Q) and (overset(rarr)P+overset(rarr)Q) ?