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If A ,Ba n dC are the vetices of a tr...

If `A ,Ba n dC` are the vetices of a triangle `A B C ,` then prove sine rule `a/(sinA)=b/(sinB)=c/(sinC)dot`

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Refer to Figure Vectors `overset(rarr)a,overset(rarr)b` and are represented by the three sides of a triangle taken in one order. Their resultant is zero. So

similarly we can get
from (i) and (ii)
or ab sin `180^(@)-c =b sin 180^(@)-A =sin 180^(@)-B`
Dividing it by abc we get
`(sin c)/(klc )=(sin A)/(a)=(sin B)/(b)` or `(a)/(sin A)=(b)/(sin B)=(c )/(sin C)`
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