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An urn contains 25 balls numbered 1 to 2...

An urn contains 25 balls numbered 1 to 25. Two balls drawn one at a time with replacement. The probability that both the numbers on the balls are odd is

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To solve the problem of finding the probability that both balls drawn from an urn containing 25 balls numbered 1 to 25 are odd, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Total Number of Balls**: The urn contains balls numbered from 1 to 25. Therefore, the total number of balls is: \[ \text{Total Balls} = 25 \] 2. **Identify the Odd Numbers**: The odd numbers between 1 and 25 are: 1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, and 25. Counting these, we find: \[ \text{Odd Numbers} = 13 \] 3. **Calculate the Probability of Drawing an Odd Number**: The probability of drawing one odd number from the urn is given by the ratio of the number of odd balls to the total number of balls: \[ P(\text{Odd}) = \frac{\text{Number of Odd Balls}}{\text{Total Balls}} = \frac{13}{25} \] 4. **Drawing with Replacement**: Since the balls are drawn with replacement, the total number of balls remains the same for each draw. Therefore, the probability of drawing an odd number remains: \[ P(\text{Odd on 2nd Draw}) = \frac{13}{25} \] 5. **Calculate the Probability of Both Draws Being Odd**: Since the draws are independent (due to replacement), the probability of both draws resulting in odd numbers is the product of the probabilities of each draw: \[ P(\text{Both Odd}) = P(\text{Odd on 1st Draw}) \times P(\text{Odd on 2nd Draw}) = \frac{13}{25} \times \frac{13}{25} = \frac{169}{625} \] ### Final Answer: Thus, the probability that both numbers on the balls drawn are odd is: \[ \frac{169}{625} \]
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VMC MODULES ENGLISH-PROBABILITY-LEVEL - 1
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