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A coin is tossed (m + n) times (m gtn). ...

A coin is tossed (m + n) times `(m gtn).` Show that the probability of at least m consecutive heads is `(n+2)//2^(m+1).`

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The correct Answer is:
`(2^(n) +(n - 1) 2^(n-2))/(2^(m + n))`
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