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A coin is tossed 2n times. The chance th...

A coin is tossed `2n` times. The chance that the number of times one gets head is not equal to the number of times one gets tails is `((2n !))/((n !)^2)(1/2)^(2n)` b. `1-((2n !))/((n !)^2)` c. `1-((2n !))/((n !)^2)1/(4^n)^` d. none of these

A

`((2n) !)/((n !)^(2)) * ((1)/(2))^(2n)`

B

`1 - ((2n)!)/((n!)^(2))`

C

`1 - ((2n)!)/((n!)^(2)) * (1)/(4^(n))`

D

None of these

Text Solution

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The correct Answer is:
C
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