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Let omega be a complex cube root of unit...

Let `omega` be a complex cube root of unity with `omega ne 1`. A fair die is thrown three times. If `r_(1), r_(2)` and `r_(3)` are the numbers obtained on the die, then the probability that `omega^(r_(1)) + omega^(r_(2)) + omega^(r_(3)) = 0` is

A

`1//18`

B

`1//9`

C

`2//9`

D

`1//36`

Text Solution

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The correct Answer is:
C
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