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Consider the determinant, Delta=|(p,q,r)...

Consider the determinant, `Delta=|(p,q,r),(x,y,z),(l,m,n)|` .
`M_(ij)` denotes the minor of an element in `i^(th)` row, and `j^(th)` column
`C_(ij)` denotes the cofactor of an element in `i^(th)` row and `j^(th)` column
the value of `q.M_12 - y.M_22+ m.M_32` is :

A

0

B

`-Delta`

C

`Delta`

D

`Delta^2`

Text Solution

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The correct Answer is:
To solve the problem, we need to find the value of \( q \cdot M_{12} - y \cdot M_{22} + m \cdot M_{32} \) where \( M_{ij} \) denotes the minor of the element in the \( i^{th} \) row and \( j^{th} \) column of the determinant \( \Delta = \begin{vmatrix} p & q & r \\ x & y & z \\ l & m & n \end{vmatrix} \). ### Step 1: Calculate the minors 1. **Calculate \( M_{12} \)**: - To find \( M_{12} \), we remove the first row and the second column from the determinant. - The remaining matrix is: \[ \begin{vmatrix} x & z \\ l & n \end{vmatrix} \] - The minor \( M_{12} \) is calculated as: \[ M_{12} = x \cdot n - z \cdot l \] 2. **Calculate \( M_{22} \)**: - To find \( M_{22} \), we remove the second row and the second column from the determinant. - The remaining matrix is: \[ \begin{vmatrix} p & r \\ l & n \end{vmatrix} \] - The minor \( M_{22} \) is calculated as: \[ M_{22} = p \cdot n - r \cdot l \] 3. **Calculate \( M_{32} \)**: - To find \( M_{32} \), we remove the third row and the second column from the determinant. - The remaining matrix is: \[ \begin{vmatrix} p & q \\ x & y \end{vmatrix} \] - The minor \( M_{32} \) is calculated as: \[ M_{32} = p \cdot y - q \cdot x \] ### Step 2: Substitute minors into the expression Now we substitute the minors into the expression \( q \cdot M_{12} - y \cdot M_{22} + m \cdot M_{32} \): \[ q \cdot M_{12} = q \cdot (x \cdot n - z \cdot l) = qxn - qzl \] \[ -y \cdot M_{22} = -y \cdot (p \cdot n - r \cdot l) = -ypn + yrl \] \[ m \cdot M_{32} = m \cdot (p \cdot y - q \cdot x) = mpy - mqx \] ### Step 3: Combine the results Now we combine all these results: \[ q \cdot M_{12} - y \cdot M_{22} + m \cdot M_{32} = (qxn - qzl) + (-ypn + yrl) + (mpy - mqx) \] Combining like terms: \[ = qxn - qzl - ypn + yrl + mpy - mqx \] ### Step 4: Rearranging the expression Rearranging gives us: \[ = (qxn - mqx) + (mpy - ypn) + (yrl - qzl) \] ### Final Result The final expression simplifies to: \[ = -\Delta \] where \( \Delta \) is the determinant of the original matrix. Thus, the value of \( q \cdot M_{12} - y \cdot M_{22} + m \cdot M_{32} \) is: \[ \text{Final Answer: } -\Delta \]
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