The volume V versus temperature T graphs for a certain amount of a perfect gas at two pressure `p_1 and p_2` are as shown in Fig. It follows from the graphs that `p_1` is greater than `p_2.`

Explanation

For a perfect gas, `PV = nRT`
`V = (nR)/OT`
Slope of V-T graph with T-axis = nR/P
For a given amount of gas, slope `prop 1/P`
Hence, `P_1 gt P_2`