`28 g "of" N_2` gas is contained in a flask at a pressure of `10 atm` and at a temperature of `57^@ C`. It is found that due to leakage in the flask, the pressure is reduced to half and the temperature to `27^@ C`. The quantity of `N_(2)` gas that leaked out is.

Options

A. `11//20 g`
B. `20//11 g`
C. `5/63 g`
D. `63 // 5 g`

Answer

D

Explanation

`P_1 V = n_2 RT_1`
`P_2 V = n_2 RT_2" " rArr " "P_1 /P_2 = (n_1 T_1)/(n_2T_2) rArr2 = (1xx330)/(n_2 300) rArr n_2 = 0.55`
`rArr" "` Number of moles leaked out ` = 1 - 0.55 = 0.45 rArr 0.45 xx 28 = 12.6 gm`