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If a system undergoes an adiabatic chang...

If a system undergoes an adiabatic change from state 1 to state 2, the work done by the gas is:

A

`U_1 - U_2`

B

`U_2 - U_1`

C

`C_V (T_2 - T_1)`

D

`1/2 (P_1 V_2 - P_1 V_1)`

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The correct Answer is:
To solve the problem of finding the work done by the gas during an adiabatic change from state 1 to state 2, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Adiabatic Process**: In an adiabatic process, there is no heat exchange with the surroundings. This means that the heat transfer \( q \) is equal to zero. 2. **Apply the First Law of Thermodynamics**: The first law of thermodynamics states: \[ q = \Delta U + W \] where \( q \) is the heat added to the system, \( \Delta U \) is the change in internal energy, and \( W \) is the work done by the system. 3. **Substitute for an Adiabatic Process**: Since \( q = 0 \) for an adiabatic process, we can rewrite the equation as: \[ 0 = \Delta U + W \] Rearranging this gives us: \[ W = -\Delta U \] 4. **Express Change in Internal Energy**: The change in internal energy \( \Delta U \) can be expressed as: \[ \Delta U = U_2 - U_1 \] where \( U_1 \) is the internal energy at state 1 and \( U_2 \) is the internal energy at state 2. 5. **Substitute Change in Internal Energy into Work Equation**: Substituting \( \Delta U \) into the work equation gives: \[ W = -(U_2 - U_1) = U_1 - U_2 \] 6. **Final Expression for Work Done**: Thus, the work done by the gas during the adiabatic process from state 1 to state 2 is: \[ W = U_1 - U_2 \] ### Conclusion: The work done by the gas during an adiabatic change from state 1 to state 2 is equal to the difference in internal energy, expressed as \( W = U_1 - U_2 \). ---

To solve the problem of finding the work done by the gas during an adiabatic change from state 1 to state 2, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Adiabatic Process**: In an adiabatic process, there is no heat exchange with the surroundings. This means that the heat transfer \( q \) is equal to zero. 2. **Apply the First Law of Thermodynamics**: ...
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