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In the following P-V diagram two adiabat...

In the following P-V diagram two adiabatics cut two isothermals at temperatures `T_(1) and T_(2)` (fig). The value of `(V_(a))/(V_(d))` will be

A

` = V_A // V_D`

B

`lt V_A // V_D`

C

`gt V_A // V_D`

D

cannot say

Text Solution

Verified by Experts

The correct Answer is:
A
BC is adiabatic process
`T_1 V_B^(gamma -1) = T_2 V_C^(gamma -1)`
` T_1/T_2 = [V_C/V_B]^(gamma - 1)" ..(i)"`
Da is adiabatic process `T_2 V_D ^(gamma-1) = T_1 V_A^(gamma -1)`
`T_1/T_2 =((V_D)/(V_A))^(gamma -1)" ...(ii)"`
By Equation (i) and (ii)
`V_C = V_B = V_D /V_A " "V_B /V_C = V_A/ V_D`
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