Three closed vessels (A),(B) and `C` are at the same temperature (T) and contain gases which obey Maxwell distribution law of velocities. Vessel (A) contains `O_(2)`, (B) only (N_2) and (C ) mixture of equal quantities of `O_(2)` and `N_(2). If the average speed of the `O_(2)` molecules in vessel (A) is `v_(1)` that of `N_(2)` molecules in vessel (B) is `v_(2)`. then the average speed of the `O_(2)` molecules in vessel (C) is.

Options

A. `((V_1 + V_2))/2`
B. `V_1`
C. `(V_1 + V_2)^(1//2)`
D. `sqrt((3KT)/M)`

Answer

B

Explanation

The average speed of molecules of an ideal gas is given by ` lt V gt = sqrt((8RT)/(pi M))`
ie., `lt V gt prop sqrtT` for same gas. Since temperature of A and C are same, average speed of `O_2` molecules will be equal A and C, i.e., `v_1`