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In a given process on an ideal gas, dW =...

In a given process on an ideal gas, dW = 0 and `dQ lt 0`. Then for the gas

A

the temperature will decrease

B

the volume will increase

C

the pressure will remain constant

D

the temperature will increase

Text Solution

Verified by Experts

The correct Answer is:
A
From the first law of thermodynamics `d Q = d U + d W`
Now since `d Q lt 0` (given)
`:." dQ is negative "rArr dU = -ve " "rArr" dU decreases " rArr " Temperature decreases "`
`:." "` The correct option is (A).
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