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A flat plate is moving normal to its pla...

A flat plate is moving normal to its plane through a gas under the action of a constant force F. The gas is kept at a very low pressure. The speed of the plate v is much less than the average speed u of the gas molecules. Which of the following options is/are true ?

A

The pressure difference between the leading and trailing faces of the plate is proportional to

B

The plate will continue to move with constant non-zero acceleration, at all times

C

At a later time external force F balances the resistive force

D

At a later time external force F balances the resistive force

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To solve the problem, we need to analyze the motion of a flat plate moving through a gas at low pressure, under the influence of a constant force \( F \). The speed of the plate \( v \) is much less than the average speed \( u \) of the gas molecules. We will examine the implications of this scenario step-by-step. ### Step-by-Step Solution: 1. **Understanding the System**: - A flat plate is moving through a gas. The gas is at very low pressure, meaning the density of gas molecules is low. - The plate experiences a constant force \( F \) and moves with speed \( v \), which is much smaller than the average speed \( u \) of the gas molecules. 2. **Pressure Difference**: - As the plate moves, it interacts with gas molecules. The leading face of the plate will experience a higher pressure due to the incoming gas molecules, while the trailing face will experience a lower pressure as the gas molecules move away. - The pressure difference \( \Delta P \) between the leading and trailing faces of the plate can be expressed in terms of the average speed of the gas molecules \( u \) and the speed of the plate \( v \). - From kinetic theory, the pressure difference is proportional to the product of the average speed of the gas molecules and the speed of the plate: \[ \Delta P \propto u \cdot v \] 3. **Resistive Force**: - The resistive force \( F_r \) acting on the plate due to the gas molecules can be derived from the pressure difference: \[ F_r = \Delta P \cdot A \] - Substituting the expression for \( \Delta P \): \[ F_r \propto A \cdot (u \cdot v) \] - This indicates that the resistive force is proportional to the product of the average speed of the gas molecules and the speed of the plate. 4. **Constant Acceleration**: - Initially, the plate may accelerate due to the net force acting on it. However, as it continues to move, the resistive force will increase until it balances the applied force \( F \). - At some later time, the external force \( F \) will balance the resistive force \( F_r \), leading to constant velocity (zero acceleration). 5. **Conclusion**: - The pressure difference between the leading and trailing faces of the plate is proportional to \( u \cdot v \). - At a later time, the external force \( F \) will balance the resistive force, resulting in no net acceleration. ### Final Statements: - The correct options based on the analysis are: - The pressure difference between the leading and trailing faces of the plate is proportional to \( u \cdot v \). - At a later time, the external force \( F \) balances the resistive force.

To solve the problem, we need to analyze the motion of a flat plate moving through a gas at low pressure, under the influence of a constant force \( F \). The speed of the plate \( v \) is much less than the average speed \( u \) of the gas molecules. We will examine the implications of this scenario step-by-step. ### Step-by-Step Solution: 1. **Understanding the System**: - A flat plate is moving through a gas. The gas is at very low pressure, meaning the density of gas molecules is low. - The plate experiences a constant force \( F \) and moves with speed \( v \), which is much smaller than the average speed \( u \) of the gas molecules. ...
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