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A fixed thermally conducting cylinder ha...

A fixed thermally conducting cylinder has a radius `R` and height `L_(0)`. The cylinder is open at its bottom and has a smaller hole at its top. A piston of mass `M` is held at a distance `L` from the top surface, as shown in the figure. The atmospheric pressure is `P_(0)`.

While the piston is at a distance `2L` from the top, the hole at the top is sealed. The piston is then released to a position where it can stay in equilibrium. In this condition, the distance of the piston from the top is

A

`((2P_0 piR^2)/(pi R^2 P_0 + Mg))(2L)`

B

`((P_0 pi R^2-Mg)/(pi R^2 P_0))(2L)`

C

`((P_0 pi R^2+Mg)/(pi R^2 P_0))(2L)`

D

`((P_0 pi R^2)/(pi R^2 P_-0 - Mg))(2L)`

Text Solution

Verified by Experts

The correct Answer is:
D

Let p be the pressure in equilibrium, then `pA = P_0 A - Mg`
Applying `P_1 V_1 = P_2 V_2`
`L'=(2P_0L)/P =((p_0)/(p_0-(Mg)/(piR^2)))(2L) = ((P_0 pi R^2)/(pi R^2 P_0 - Mg)) (2L)`
Therefore, option (D) is correct.
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