One mole of mono-atomic ideal gas is taken along two cyclic processes and as shown in the PV diagram. The processes involved are purely isobaric, isothermal or adiabatic.

Match the paths in Column I with the magnitudes of the work done in column II and select the correct answer using the codes given below the lists.

Answer

`A-S; B-R; C-Q; D-P`

Explanation

A-S, B-R, C-Q, D-P
Apply `PV^(1+2//3)` = Constant for F to H.
`(32 P_0 )V_0^(5//3) = P_0V_H^(5//3)rArr V_H = 8H_0`
For path FG, PV = constant
`rArr " "(32 P_0 )V_0 = P_0 V_G " "rArr" "V_G = 32 V_0`
Work done in GE = 31 `p_0 V_0`
Work done in GH `=24 p_0 v_0`

Work done in `"FH"=(P_H V_H - P_FV_F)/((-2//f))=36 P_0 V_0`
Work done in `"FG = RT In"((V_G)/(V_F)) =160 P_0 V_0 "In 2"`.