At `27^(@)C` two moles of an ideal monatomic gas occupy a volume. V The gas expands adiabatically to a volume 2V. Calculate (i) Final temperature of the gas (ii) change its internal energy and (iiI) Workd done by the gas during this process. Given `R = 8.31 J//"mol" K, (2)^(2//3) = 1.587`

Answer

`-2767`

Explanation

Given `T_1 = 27^@C = 300 K, V_1 = V, V_2 = 2V`
Change in internal energy
`Delta U - (2) (3/2 R)(T_2 - T_1)`
`Delta U = 2 (3/2 )(8.31)(189-300)J`
`Delta U =-2767 J`