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During an experiment, an ideal gas is found to obey an additional law `VP^2` =constant. The gas is initially at a temperatur T and volume V. When it expands to a volume `2V`, the temperature becomes___________`.^@C`.

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The correct Answer is:
`sqrt2 T`
`VP^2` = constant
Putting, `p = (nRT)/V`, We have ` T^2/V =` constant or `T prop sqrtV`
So, if V is doubled, T becomes T times.
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