A simple pendulum of length L and having a bob of mass m is suspended in a car. The car is moving on a circular trrack of radius R with a uniform speed v. If the pendulum makes small oscillations in a radial direction about its equilibrium position, its time period of oscillation is

Explanation

The bob of the simple pendulum will experience the acceleration due to gravity and the centripetal acceleration provided by the circular motion of the car.
Acceleration due to gravity = g
Centripetal acceleration =`(v^(2))/(R)` Where,
v is the uniform speed of the car
R is the radius of the track
Effective acceleration`(a_(eff))` is given as `a_(eff)=sqrt(g^(2)+((v^(2))/(R))^(2))`
`T=2pisqrt((I)/(a_(eff)))`
Time period, Where, // is the length of the pendulum `therefore` Time period, `T=2pisqrt((I)/((g^(2)+(v^(2))/(R^(2)))1//2))`.