Displacement-time equation of a particle execution SHM is x=A sin(`omegat+pi/6)`
Time taken by the particle to go directly from
`x = -A/2 to x = + A/2 is `

Options

A. `(pi)/(3omega)`
B. `(pi)/(2omega)`
C. `(2pi)/(omega)`
D. `(pi)/(omega)`

Answer

A

Explanation

For SHM,`x=Asinomegat`, for x=0 to `x=(A)/(2)` `Rightarrow` `t=(T)/(12)` where `T=(2pi)/(omega)`
It will be same for `x=-(A)/(2)`to x=0. Hence required time `t=2xx(T)/(12)=(T)/(6)=(pi)/(3omega)`