An object of mass 0.2 kg executes simple harmonic oscillation along the x-axis with a frequency `(25)/pi`. At the position x = 0.04m, the object has kinetic energy 0.5J and potential energy 0.4J. amplitude of oscillation is (potential energy is zero mean position).

Options

A. 6 cm
B. 4 cm
C. 8 cm
D. 2 cm

Answer

A

Explanation

`k=(1)/(2)momega^(2)(A^(2)-x^(2))=0.5`, `U=(1)(2)momega^(2)x^(2)=0.4J`
`Rightarrow` `(1)/(2)momega^(2)A^(2)=0.9` `Rightarrow` `(1)/(2)xx0.2xx50^(2)A^(2)=0.9(omega =2pif)` `Rightarrow` `A=(3)/(50)m=6cm`