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Two simple harmonic motions y(1) = Asino...

Two simple harmonic motions `y_(1) = Asinomegat` and `y_(2)` = Acos`omega`t are superimposed on a particle of mass m. The total mechanical energy of the particle is

A

`(1)/(2)momega^(2)A^(2)`

B

`m omega^(2)A^(2)`

C

`(1)/(4)momega^(2)A^(2)`

D

zero

Text Solution

Verified by Experts

The correct Answer is:
B
Phase difference between the two SHM’s =`90^(@)` Therefore `A_(R)=sqrt2A` `E=(1)/(2)momega^(2)A_(R)^(2)=momega^(2)A^(2)`
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