Home
Class 12
PHYSICS
A particle is subjected to two simple ha...

A particle is subjected to two simple harmonic motions in the same direction having equal amplitudes and equal frequency. If the resulting amplitude is equal to the amplitude of individual motions, the phase difference between them is

A

`(pi)/(3)`

B

`(2pi)/(3)`

C

`(pi)/(6)`

D

`(pi)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
B

`A=sqrt(A^(2)+A^(2)+2A^(2)cosphi)Rightarrow cosphi=(1)/(2)`
Promotional Banner

Topper's Solved these Questions

  • SIMPLE HARMONIC MOTION

    VMC MODULES ENGLISH|Exercise LEVEL (2)|40 Videos
  • SIMPLE HARMONIC MOTION

    VMC MODULES ENGLISH|Exercise 6-previous year question|56 Videos
  • SIMPLE HARMONIC MOTION

    VMC MODULES ENGLISH|Exercise LEVEL 0 LONG ANSWER TYPE|2 Videos
  • ROTATIONAL MOTION

    VMC MODULES ENGLISH|Exercise JEE Advanced (Archive) (True/False Type)|3 Videos
  • SYSTEM OF A PARTICLES & ROTATIONAL MOTION

    VMC MODULES ENGLISH|Exercise IN-CHAPTER EXERCISE F|10 Videos

Similar Questions

Explore conceptually related problems

A particle is subjected to two simple harmonic motions in the same direction having equal amplitudes and equal frequency. If the resultant amplitude is equal to the amplitude of the individual motions, find the phase difference between the individual motions.

A particle is subjected to two simple harmonic motion in the same direction having equal amplitudes and equal frequency. If the resultant amplitude is equal to the amplitude of the individual motions. Find the phase difference between the individual motions.

A particle is subjected to two simple harmonic motions of the same frequency and direction. The amplitude of the first motion is 4.0 cm and that of the second is 3.0 cm . Find the resultant amplitude if the phase difference between the two motion is (a) 0^(@) (b) 60^(@) ( c) 90 ^(@) (d) 180^(@)

A particle is subjected to two simple harmonic motions of same time period in the same direction. The amplitude of the first motion is 3.0 cm and that of the second is 4.0 cm. Find the resultant amplitude if the phase difference between the motion is a. 0^@, b. 60^@, c. 90^@

Two waves of equal amplitude when superposed, give a resultant wave having an amplitude equal to that of either wave. The phase difference between the two waves is

The frequency of amplitude modulated wave is equal to

Three simple harmonic motions in the same direction having the same amplitude and same period are superposed. If each differ in phase from the next by 45^(@) , then

Two waves of equal amplitude A, and equal frequency travel in the same direction in a medium. The amplitude of the resultant wave is

Two simple harmonic motions with the same frequency act on a particle at right angles i.e., along X-axis and Y-axis. If the two amplitudes are equal and the phase difference is pi//2 , the resultant motion will be

Two bodies performing S.H.M. have same amplitude and frequency. Their phases at a certain instant are as shown in the figure. The phase difference between them is

VMC MODULES ENGLISH-SIMPLE HARMONIC MOTION -LEVEL (1)
  1. The displacement of a particle varies with time according to the relat...

    Text Solution

    |

  2. Two simple harmonic motions y(1) = Asinomegat and y(2) = Acosomegat ar...

    Text Solution

    |

  3. A particle is subjected to two simple harmonic motions in the same dir...

    Text Solution

    |

  4. A particle is acted simultaneously by matually perpendicular simple ha...

    Text Solution

    |

  5. A mass m attached to a spring of spring constant k is stretched a dist...

    Text Solution

    |

  6. Frequency of a particle executing SHM is 10 Hz. The particle is suspen...

    Text Solution

    |

  7. Two masses M and m are suspended together by massless spring of force ...

    Text Solution

    |

  8. Three masses of 500 g, 300 g and 100 g are suspended at the end of a s...

    Text Solution

    |

  9. A mass is suspended separately by two springs of spring constant k(1) ...

    Text Solution

    |

  10. When a mass m is connected individually to two springs S(1) and S(2), ...

    Text Solution

    |

  11. Four massless springs whose force constants are 2k, 2k, k and 2k respe...

    Text Solution

    |

  12. A spring of force constant k is cut into two pieces such that one piec...

    Text Solution

    |

  13. A spring of spring constant k is cut into n equal parts, out of which ...

    Text Solution

    |

  14. In the figure shown the time period and the amplitude respectively, wh...

    Text Solution

    |

  15. Find the time period of oscillation of block of mass m. Spring, and pu...

    Text Solution

    |

  16. A pendulum has a period T for small oscillations. An obstacle is place...

    Text Solution

    |

  17. The time period of a simple pendulum of length L as measured in an ele...

    Text Solution

    |

  18. A pendulum suspended from the ceiling of the train has a time period o...

    Text Solution

    |

  19. A simple pendulum has time period T = 2s in air. If the whole arrangem...

    Text Solution

    |

  20. The bob of a simple pendulum is displaced from its equilibrium positio...

    Text Solution

    |